8p^2+16p-71=-7

Solution for 8p^2+16p-71=-7 equation:

8p^2+16p-71=-7

We move all terms to the left:

8p^2+16p-71-(-7)=0

We add all the numbers together, and all the variables

8p^2+16p-64=0

a = 8; b = 16; c = -64;
Δ = b2-4ac
Δ = 162-4·8·(-64)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-48}{2*8}=\frac{-64}{16}
=-4
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+48}{2*8}=\frac{32}{16}
=2
$